Answer:
- 4/5x
Step-by-step explanation:
So, this is a simple thing as long as you convert it into slope-int form. So, I am guessing from the question that the equation is
4x + 5y = 5
From here, you have to isolate y and leave all of the other variable by themselves. So, first you would subtract 4x from both sides and that leaves you with
5y = 5 -4x
Then, to isolate 5, you would divide 5 by both sides to get
y = 1- 4/5x
Now, you would put this is slope intercept form: y = mx + b to get
y = - 4/5 x + 1
Now, you can see that the slope is - 4/5x
Hope I helped!!!!!
to the risk of sounding a bit redundant.
[tex]\bf 4x+5y=5\implies 5y=-4x+5\implies y=\cfrac{-4x+5}{5}\\\\\\\stackrel{\textit{distributing the denominator}}{y=\cfrac{-4x}{5}+\cfrac{5}{5}}\implies \stackrel{slope}{y=\stackrel{\downarrow }{-\cfrac{4}{5}}x}+1\impliedby \begin{array}{|c|ll}\cline{1-1}slope-intercept~form\\\cline{1-1}\\y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}}\\\\\cline{1-1}\end{array}[/tex]
