Given, concentration of HCl = 0.10 M
Mass of Mg(OH)₂ = 0.10 g
Molar mass of Mg(OH)₂ = 58.3197 g/mol
Moles = mass /molar mass
Mole of Mg(OH)₂ = 0.10 g/ 58.3197 g/mol
Mole of Mg(OH)₂ = 1.71
Mg(OH)₂(s) + 2HCl(aq) → MgCl₂(aq) + 2H₂O(l)
According to the balanced equation 1 moles of Mg(OH)₂ reacts with 2 moles of HCl.
Therefore, 1.71 moles of Mg(OH)₂ reacts with (2 x 1.71) or 3.42 moles of HCl
Molarity = moles / volume in L
Volume of HCl = 3.42 moles of HCl / 0.10 M HCl
Volume of HCl = 34.2 L or 34200 ml
34200 ml of “stomach acid” reacts with a tablet that contains 0.10 g of magnesium hydroxide.
