For this case we have the following equation, in a linear way:
[tex]y + 2 = 3 (x-1)[/tex]
This expression can be written in the form [tex]y = mx + b[/tex]
Where "m" is the slope and "b" is the cut point with the y axis.
Rewriting the given expression we have:
[tex]y + 2 = 3x-3\\y = 3x-3-2\\y = 3x-5[/tex]
Thus, the slope is 3 and the cut point is -5.
To graph, we must find two points through which the line passes, so, we perform the following steps:
Step 1:
We do [tex]x = 0[/tex]
[tex]y = 3 (0) -5\\y = 0-5\\y = -5[/tex]
Thus, the point [tex](x1, y1) = (0, -5)[/tex]
Step 2:
We do[tex]y = 0[/tex]
[tex]0 = 3x-5\\5 = 3x[/tex]
[tex]x =\frac{5}{3}[/tex]
Thus, the point [tex](x2, y2) = (\frac{5}{3},0)[/tex]
Answer:
See attached image
