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63. Liv volunteered for h hours. Gavin volunteered for 4 fewer hours than Liv. Together they volunteered a total of 50 hours. Write an equation that could be used to find the total number of hours that the two teens worked.

64. Brendan rides his bike at a constant speed, s, for 0.75 hours. Write a formula that could be used to find the distance that he rides.

65. Alexis swam m meters and Sade swam half as many meters as Alexis. Together they swam a total of 200 meters. Write an equation that could be used to find the total number of meters that Alexis swam.

66. Grace ate five more peanuts than Keona. Grace ate g peanuts. Together they are 40 peanuts. Write an equation that could be used to find the number of peanuts that Grace ate.

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63.  Liv volunteered for h hours. If Gavin volunteered for 4 fewer hours than Liv, then Gavin volunteered (h-4) hours.  Together they volunteered h+(h-4) hours that is 50 hours.

Thus, the equation is

h+(h-4)=50.

64. Brendan rides his bike at a constant speed, s, for 0.75 hours. The speed multiplied by the time gives the distance, then

[tex]d=0.75\cdot s.[/tex]

65. Alexis swam m meters. If Sade swam half as many meters as Alexis,  then Sade swam [tex]\dfrac{m}{2}[/tex] meters. In total they both swam [tex]m+\dfrac{m}{2}[/tex] meters that is 200 meters.

Therefore, the equation is

[tex]m+\dfrac{m}{2}=200.[/tex]

66.   Grace ate g peanuts. If Grace ate five more peanuts than Keona, then Keona ate 5 less peanuts than Grace. Thus, Keona ate (g-5) peanuts. Together they ate g+(g-5) peanuts that is 40 peanuts.

The equation that represents this problem is

g+(g-5)=40