Consider the polynomial 16x2 - 1 what is the value of ac what is the value of b
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Answer:
ac= -16
b=0
[tex](4x+1)(4x-1)[/tex]
Step-by-step explanation:
[tex]16x^2 -1[/tex]
WE write the given polynomial in standard form ax^2 + bx+c
there is no x term so we include 0x
the given expression becomes
[tex]16x^2+0x-1[/tex]
The value of a= 16 , b= 0 and c=-1
[tex]ac= a*c = 16 * (-1) = -16[/tex]
The value of b = 0
Two number to multiply to get ac = -16 are 4 and -4
When we add two numbers we will get
-4 + 4= 0
using factors -4 and 4 , the expression becomes
[tex]16x^2-4x+4x-1[/tex]
[tex](16x^2-4x)+(4x-1)[/tex]
Factor out GCF
[tex]4x(4x-1)+1(4x-1)[/tex]
[tex](4x+1)(4x-1)[/tex] is the factored form