Let the bottom section has length x feet.
1. The top section is [tex]\dfrac{1}{6}[/tex] the length of the bottom section, then the length of the top section is [tex]\dfrac{1}{6}x.[/tex]
2. The middle section is [tex]\dfrac{1}{2}[/tex] the length bottom section, then the middle section has length [tex]\dfrac{1}{2}x.[/tex]
3. The total length of the rocket is
[tex]x+\dfrac{1}{6}x+\dfrac{1}{2}x[/tex]
that is 240 feet.
Thus, you have the equation
[tex]x+\dfrac{1}{6}x+\dfrac{1}{2}x=240.[/tex]
4. Solve it. Multiply this equation by 6:
[tex]6x+x+3x=240\cdot 6,\\\\10x=1,440.[/tex]
Divide it by 10:
[tex]x=144\ ft.[/tex]
The length of the bottom section is 144 feet, then the length of the top section is
[tex]\dfrac{1}{6}x=\dfrac{1}{6}\cdot 144=24\ ft.[/tex]
Answer: The top section has length 24 feet
Answer:
Length of top section of rocket = 24 ft
Explanation:
We have length of top section = One -sixth the length of the bottom section
Length of middle section = One -half the length bottom section.
Let length of bottom section be x.
So length of top section [tex]=\frac{1}{6}*x=\frac{x}{6}[/tex]
Length of middle section [tex]=\frac{1}{2}*x=\frac{x}{2}[/tex]
We have total length of rocket = 240 ft
Also we have, total length [tex]=x+\frac{x}{6} +\frac{x}{2}\\\\= \frac{6x}{6}+\frac{x}{6} +\frac{3x}{6}\\\\= \frac{10x}{6}\\\\=\frac{5x}{3}[/tex]
So, [tex]\frac{5x}{3}= 240\\ \\ x=144ft[/tex]
Length of bottom section = 144 ft
Length of top section [tex]=\frac{1}{6}*144=24ft[/tex]
Length of top section of rocket = 24 ft
