Answer:
there are only 4 whole numbers whose squares and cubes have the same number of digits.
Explanations:
let 0, 1, 2 and 4∈W (where W is a whole number), then
[tex]0^2=0[/tex], [tex]0^3=0[/tex],
[tex]1^2=1[/tex], [tex]1^3=1[/tex],
[tex]2^2=4[/tex], [tex]2^3=8[/tex],
[tex]4^2=16[/tex], [tex]4^3=64[/tex].
You can see from the above that only four whole numbers are there whose squares and cubes have the same number of digits
