Answer:
1. No factors
2. (4x^3 - 5y^2) ( 16x^6 + 20x^3y^2 + 25y^4)
3. x = 0 (multiplicity 2), -13/9, -2/11
Step-by-step explanation:
2. Using the identity
a^3 - b^3 = (a - b)(a^2 + ab + b^2) with a = 4x^3 and b = 5y^2
3. Using that either one of the factors can = zero.
