Hey there!!
Given is an recursive formula :-
... b(n) = b(n-1) - 7
In this equation, 'n' is the number of the term we will need to find and '-7' is the common difference.
... b(1) = -2
We get to know that the first term is -2.
Now, we will find the 2nd term :-
... b(2) = b(2-1) - 7
... b(2) = b(1) - 7
We know b(1) is -2.
... b(2) = -2-7
... b(2) = -9
The second terms is -9 b(2) = -9
Now, let's find the third term :-
... b(3) = b(3-1) - 7
... b(3) = b(2) - 7
We know b(2) is -9
... b(3) = -9-7
... b(3) = -16
The third terms is -16.
Hence, the third term and the answer is -16.
Hope my answer helps!!
