A uniform distribution is defined over the interval from 6 to 10.
a. what are the values for a and b?
b. what is the mean of this uniform distribution?
c. what is the standard deviation?
d. show that the total area is 1.00 (use the area formula)
e. find the probability of a value more than 7 f. find the probability of a value between 7 and 9

Respuesta :

Answer:

Refer below

Step-by-step explanation:

a) a and b are the lower and higher values of the interval for which uniform distribution is defined.

Here a= 6 and b =10

b) Mean of the uniform distribution= (a+b)/2 = (6+10)/2 =8

Or int x (1/4) dx = x^2/8 = 8

c) Variance of the uniform distribution = (b^2-a^2)/12 = (100-64)/12

= 36/12 =3

Std dev = sq rt of 3 = 1.732

d) To find total area

PDF of the distribution = 1/(b-a) = 1/4, 6<x<10

Area = \int 6 to 10 of 1/4 dx

= x/4

Subtitute limits

= (10-6)/4 =1

So total area = 1

d)P(X>7) = int 7 to 10 of 1/4 dx = 3/4

e) P(7<x<9) = Int 7 to 9 of 1/4 dx = 2/4 = 1/2


Probabilities are used to determine the chances of events

The values of a and b

The interval is given as 6 to 10.

So, the values of a and b are 6 and 10, respectively.

The mean

For a uniform distribution, the mean is:

[tex]\bar x = \frac{a + b}{2}[/tex]

So, we have:

[tex]\bar x = \frac{6 + 10}{2}[/tex]

[tex]\bar x = 8[/tex]

Hence, the mean is 8

The standard deviation

For a uniform distribution, the standard deviation is:

[tex]\sigma = \sqrt{\frac{b^2 - a^2}{12}}[/tex]

So, we have:

[tex]\sigma = \sqrt{\frac{10^2 - 6^2}{12}}[/tex]

[tex]\sigma = 2.31[/tex]

Hence, the standard deviation is 2.31

The total area

This is calculated as:

[tex]A = \int\limits^b_a \frac{1}{b - a}\ dx[/tex]

So, we have:

[tex]A = \int\limits^{10}_6 \frac{1}{10 - 6}\ dx[/tex]

[tex]A = \int\limits^{10}_6 \frac{1}{4}\ dx[/tex]

Factor out 1/4

[tex]A = \frac{1}{4}\int\limits^{10}_6 \ dx[/tex]

Integrate

[tex]A = \frac{1}{4} * x|\limits^{10}_6[/tex]

Expand

[tex]A = \frac{1}{4} * (10 - 6)[/tex]

[tex]A = 1[/tex]

Hence, the total area of the distribution is 1.00

The probability of a value more than 7

This is calculated as:

[tex]P(x > 7) = \frac{1}{4} * x|\limits^{10}_7[/tex]

Expand

[tex]P(x > 7) = \frac{1}{4} * (10 - 7)[/tex]

[tex]P(x > 7) = 0.75[/tex]

Hence, the probability of a value more than 7 is 0.75

The probability of a value between 7 and 9

This is calculated as:

[tex]P(7 < x < 9) = \frac{1}{4} * x|\limits^9_7[/tex]

Expand

[tex]P(7 < x < 9) = \frac{1}{4} * (9 - 7)[/tex]

[tex]P(7 < x < 9) = 0.50[/tex]

Hence, the probability of a value between 7 and 9 is 0.50

Read more about probability at:

https://brainly.com/question/25870256