Answer: [tex]\frac{63}{64}[/tex]
Step-by-step explanation:
"At least one" means:
(1g & 5b) or (2g & 4b) or (3g & 3b) or (4g & 2b) or (5g & 1b) or (6g & 0b)
which is the same as: not(0g & 6b)
not (0g & 6b)
= 1 - [tex][(\frac{1}{2})^{0}*(\frac{1}{2})^{6} ][/tex]
= 1 - [tex]1 * \frac{1}{64}[/tex]
= 1 - [tex]\frac{1}{64}[/tex]
= [tex]\frac{63}{64}[/tex]
