Respuesta :
We are given that
Max's grade on the first math exam was a 94
so, first exam grade =94
His grade on his seond math exam was an 89
so, second exam grade =89
change in grade=(first exam grade)-(second exam grade)
change in grade=94-89
change in grade=5
Percentage = ( change in grade)/( first exam grade) *100
so, percentage is
[tex]=\frac{5}{94}\times 100[/tex]
so,
the percent of change in Max's grade to the nearest whole percentage was 5%..........Answer
Answer:
The percent of change in grade was "5% decrease"
Step-by-step explanation:
Max's grade on the first math exam was 94 and his grade on his second math exam was 89.
So, the grade is decreased by (94 - 89) = 5
For finding the percentage of change in grade, we will just divide the "grade decreased" by the "initial grade" and then multiply that by 100%.
So, [tex]\frac{5}{94}\times 100\% = \frac{500}{94}\%= 5.31...\% \approx 5\%[/tex]
Thus, the percent of change in Max's grade to the nearest whole percent was 5% decrease.
