The position-time equation for a certain train is xf=2.8m+(8.1m/s)t+(2.9m/s^2)t^2.
What is the initial velocity of this train?
What is its acceleration?
the formula without numbers is [tex]xf = xi + vxi(t) + \frac{1}{2} (a) {t}^{2} [/tex] do the initial velocity would be 8.1 m/s and the acceleration would be 2.9 m/s^2
