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For many years chloroform (CHCl3) was used as an inhalation anesthetic in spite of the fact that it is also a toxic substance that may cause severe liver, kidney, and heart damage. Calculate the percent composition by mass of this compound to four significant figures. The following molar masses should be used in your calculation: H = 1.008 g/mol, C = 12.01 g/mol, Cl = 35.45 g/mol.

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Hey there!:

Molar mass:

CHCl3 = ( 12.01 * 1 )+ (1.008 * 1 ) + ( 35.45 * 3 ) => 119.37 g/mol

C% =  ( atomic mass C / molar mass CHCl3 ) * 100

For C :

C % =  (12.01 / 119.37 ) * 100

C% = ( 0.1006 * 100 )

C% =  10.06 %

For H :

H% = ( atomic mass H / molar mass CHCl3 ) * 100

H% = ( 1.008 / 119.37 ) * 100

H% = 0.008444 * 100

H% = 0.8444 %

For Cl :

Cl % ( molar mass Cl3 / molar mass CHCl3 ):

Cl% =  ( 3 * 35.45 / 119.37 ) * 100

Cl% =  ( 106.35 / 119.37 ) * 100

Cl% = 0.8909 * 100

Cl% = 89.9%


Hope that helps!

abidemiokin

The percent composition by mass of carbon, hydrogen, and chlorine in the compound is 10.06%, 0.8444%, and 89.09% respectively.

Given the chloroform CHCl₃

Get the molar mass of chloroform:

The molar mass of chloroform = 12.01 + 1.008 + 3(35.45)

The molar mass of chloroform = 12.01 + 1.008 + 106.35

The molar mass of chloroform = 119.368g/mol

Get the percentage composition of each of the element as shown:

For the Carbon atom:

% Carbon = 12.01/119.368 * 100%

% Carbon = 1201/119.368

%Carbon = 10.06%

For the Hydrogen atom:

% Hydrogen = 1.008/119.368 * 100%

% Hydrogen = 100.8/119.368

% Hydrogen = 0.8444%

For the Chorine atom:

% Chiorine = 106.35/119.368 * 100%

% Chlorine = 10635/119.368

% Chlorine = 89.09%

Hence the percent composition by mass of carbon, hydrogen, and chlorine in the compound is 10.06%, 0.8444%, and 89.09% respectively.

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