Tony and Mike, factored the trinomial [tex]8x^2 - 12x - 8[/tex]
Tony factored it as 4(x - 2)(2x + 1) and
Mike factored it as (x - 2)(8x + 4)
[tex]8x^2 - 12x - 8[/tex]
GCF is 4. We factor out 4
[tex]4(2x^2 - 3x - 2)[/tex]
2*-2=-4. We find out two factors whose product is -4 and sum is -3
two factors are -4 and 1. Split middle term -3x using two factors
[tex]4(2x^2 - 4x + 1x - 2)[/tex]
Group first two terms and last two terms
[tex]4[(2x^2 - 4x) + (1x - 2)][/tex]
Factor out GCF from each group
[tex]4[2x(x - 2) + 1(x - 2)[/tex]
4(2x+1)(x-2)
Tony factored it correctly
Mike factored it as (x − 2)(8x + 4)
Mike factor 8x+4 further. GCF of 8 and 4 is 4
So it becomes 4(2x+1)
Mike not factored it completely
