Hey there!:
The reaction is as follows:
N2(g)+ 3 H2(g) ⇌ 2 NH3(g)
At equilibrium, the concentrations of the different species are as follows.:
[NH3] = 0.105 M
[N2] = 1.1 M
[H2] = 1.50 M
The equilibrium constant for the reaction is given as follows:
Keq = [NH3]² / [N2] [H2]³
Keq = (0.105)² / [1.1] [1.50]³
Keq = 0.00296 or 0.0030
The equilibrium constant for the reaction at this temperature is 0.0030.
Hope that helps!
