Answer:
Consider two adjacent rectangular rooms having Length=L, and, Breadth = B
Now Suppose the wall which is in between two rooms has a height or length =H.
Breadth of wall = B [ if the wall doesn't exceed the breadth of room]
Considering two rooms to be identical,
Area of each room= L × B square unit
Area of each tile = 1×1=1 square unit
Number of tiles required= L B ÷ 1= LB tiles( product of length and breadth of room is number of tiles required)
Suppose if,LB= N
B= N/L .................(1)
Area of wall(W) = B×H= B H square unit
B =W/H ......................(2)
Equating (1) and (2)
⇒N/L = W/ H
⇒H =[tex]\frac{WL}{N}[/tex]
⇒H =[tex]\frac{WL}{LB}[/tex]
⇒H = W/B
⇒ H =[tex]\frac {\text{ Area of Wall}}{\text{Breadth of room or wall}}[/tex]
