Which of the following is the electron configuration of an electrically neutral alkaline earth metal

A. 1s2 2s1

B. 1s2 2s2 2p2

C. 1s2 2s2 2p6 3s1

D. 1s2 2s2 2p6 3s2 3p6 4s2

I feel like the answer is D, but I’m not sure.

Respuesta :

Answer:

Option d, 1s2 2s2 2p6 3s2 3p6 4s2

Explanation:

Alkaline earth metals belong to group 2 of the periodic table. Elements belonging to group 2 are beryllium, magnesium, calcium, strontium and barium and radium.

Alkaline earth metals have 2 valence electrons and these two electrons are filled in outermost s sub shell.

General electronic configuration of alkaline earth metal: ns^2

In ionized state, number of electrons in s sub shell will not be 2.

Among the given, only 1s2 2s2 2p6 3s2 3p6 4s2, has 2 electrons in s sub shell. So, it an electronic configuration of neutral alkaline earth metal.

The correct answer to the question is Option D. 1s² 2s²2p⁶ 3s²3p⁶ 4s²

Alkaline earth metals are metals belonging to the group 2 of the periodic table.

They have 2 valence electrons.

Now, we shall determine which of the option given above that has  valency of 2 electrons

For Option A

1s² 2s¹

Valence electron shell = 2s¹

Valence electron = 1

For Option B

1s² 2s²2p²

Valence electron shell = 2s²2p²

Valence electron = 2 + 2

Valence electron = 4

For Option C

1s² 2s²2p⁶ 3s¹

Valence electron shell = 3s¹

Valence electron = 1

For Option D

1s² 2s²2p⁶ 3s²3p⁶ 4s²

Valence electron shell = 4s²

Valence electron = 2

From the illustraton made above, we can see that only Option D has a valence electron of 2.

Therefore, the correct answer to the question is Option D. 1s² 2s²2p⁶ 3s²3p⁶ 4s²

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