Respuesta :
Answer:
Option d, 1s2 2s2 2p6 3s2 3p6 4s2
Explanation:
Alkaline earth metals belong to group 2 of the periodic table. Elements belonging to group 2 are beryllium, magnesium, calcium, strontium and barium and radium.
Alkaline earth metals have 2 valence electrons and these two electrons are filled in outermost s sub shell.
General electronic configuration of alkaline earth metal: ns^2
In ionized state, number of electrons in s sub shell will not be 2.
Among the given, only 1s2 2s2 2p6 3s2 3p6 4s2, has 2 electrons in s sub shell. So, it an electronic configuration of neutral alkaline earth metal.
The correct answer to the question is Option D. 1s² 2s²2p⁶ 3s²3p⁶ 4s²
Alkaline earth metals are metals belonging to the group 2 of the periodic table.
They have 2 valence electrons.
Now, we shall determine which of the option given above that has valency of 2 electrons
For Option A
1s² 2s¹
Valence electron shell = 2s¹
Valence electron = 1
For Option B
1s² 2s²2p²
Valence electron shell = 2s²2p²
Valence electron = 2 + 2
Valence electron = 4
For Option C
1s² 2s²2p⁶ 3s¹
Valence electron shell = 3s¹
Valence electron = 1
For Option D
1s² 2s²2p⁶ 3s²3p⁶ 4s²
Valence electron shell = 4s²
Valence electron = 2
From the illustraton made above, we can see that only Option D has a valence electron of 2.
Therefore, the correct answer to the question is Option D. 1s² 2s²2p⁶ 3s²3p⁶ 4s²
Learn more: https://brainly.com/question/11114869