kp2004
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Find the point, M, that divides segment AB into a ratio of 5:5 if A is at (0, 15) and B is at (20, 0).

A) (35, 10)
B) (20, 10)
C) (10, 7.5)
D) (17.5, 5)

Respuesta :

C

a ratio of 5 : 5 simplifies to 1 : 1, which basically means we require the midpoint of the line segment

using the midpoint formula

M = [[tex]\frac{1}{2}[/tex] (0 + 20 ), [tex]\frac{1}{2}[/tex] (15 + 0)] = (10, 7.5 )

Answer:

Option C). (10, 7.5)

Step-by-step explanation:

We have to find the coordinates of point M that divides the segment AB into a ratio of 5:5.

Vertices A and B are (0, 15) and (20, 0)

Ratio 5:5 is simply the ratio 1:1 means point M is the midpoint of segment AB.

So x-coordinate of M will be [tex]\frac{(20+0)}{2}=10[/tex]

and y - coordinate will be = [tex]\frac{(15+0)}{2}=7.5[/tex]

Therefore Option C. (10, 7.5) are the coordinates of point M.

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