Scientists in a test lab are testing the hardness of a surface before constructing a building. Calculations indicate that the entire structure would sink by a certain amount for every additional floor that is added. If the maximum permissible limit for depression of the structure is 20 centimeters, how many floors can be safely added to the building?

A.14
B.15
C.18
D.23

Thus each supplementary level will obtain the construction of tub with x so make the unit "cm". It can be x cm. Presently we understand that the highest cavity is 20 cm, and it is also x*y, where y is the number of floors. Consequently, we possess x*y=20 since the number of floors is:

20/x =

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mateolara11 mateolara11 · Answer 2 · 2020-02-13T21:33:32+01:00

Answer:

C. 18

Explanation:

Hi, you haven't provided the depression per floor so I'll explain to you how to do it for a given depression/floor and you can extend it to your problem by applying the same steps. Since each additional floor generates a constant depression the depression generated for one floor (depression/floor) multiply by the number of extra floors will give you the total depression:

(depression per floor)*(number of floors added) = Total depression

Because the maximum depression accepted is 20 cm:

(depression per floor)*(number of floors added) < 20 cm

If the depression per floor is one centimeter:

1 cm * (number of floors added) < 20 cm

number of floors added < 20 cm

For this example, the answer would be 18 floors because is the maximum number of floors, in the list of options, that doesn't contradict the inequality (18 cm < 20 cm)