Answer:
a) Acceleration, a = -u/9, where u is the initial velocity
b) Acceleration = 0.741 m/s², Initial velocity = 6.67 m/s
Explanation:
We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.
a) We have v = 0 m/s, t = 9 s
So, 0 = u + a x 9
Acceleration, a = -u/9, where u is the initial velocity
b) We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
s = 30 m , u = -9a, t =9 s
So, [tex]30= -9a*9+\frac{1}{2} *a*9^2\\ \\ 30=-40.5a\\ \\ a=-0.741m/s^2[/tex]
u = -9a = 6.67 m/s
So acceleration = 0.741 m/s², Initial velocity = 6.67 m/s
