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EXAM PLEASE HELP 98 POINTS! An 8.0 cm object is 40.0 cm from a concave mirror that has a focal length of 10.0 cm. Its image is 16.0 cm in front of the mirror.

The height of the image produced by the mirror, to the nearest tenth, is
cm.

(NOT 9.6)

Respuesta :

Overhollowhills
hi/hobject=-si/so

hi=(-16/40)(8)= -3.2cm
barreras364

Answer:

3.2

Explanation:

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