Answer:
The two possible compounds are;
1) Dimethyl Ether H₃C--O--CH₃
2) Ethanol H₃C--CH₂--OH
Solution:
Step 1: Calculate Moles of each Element;
Moles of C = %C ÷ At.Mass of C
Moles of C = 52.14 ÷ 12.01
Moles of C = 4.341 mol
Moles of H = %H ÷ At.Mass of H
Moles of H = 13.13 ÷ 1.01
Moles of H = 13.00 mol
Moles of O = %O ÷ At.Mass of O
Moles of O = 34.73 ÷ 16.0
Moles of O = 2.170 mol
Step 2: Find out mole ratio and simplify it;
C H O
4.341 13.00 2.170
4.341/2.170 13.00/2.170 2.170/2.170
2 5.99 1
2 6 1
Hence, Empirical Formula = C₂H₆O
Result:
As the molecular mass of compound is not given therefore, we can assume and guess the empirical formula to be the molecular formula. Hence, possible compounds are,
1) Dimethyl Ether H₃C--O--CH₃
2) Ethanol H₃C--CH₂--OH
