Answer:
It's true that [tex]JK \cong MN[/tex]
Step-by-step explanation:
If the lengths of two line segments are equal, then they are said to be congruent to each other.
[tex]JK[/tex] has endpoints as [tex]J(-1, 10)[/tex], [tex]K(-5,2)[/tex] and [tex]MN[/tex] has endpoints as [tex]M(9,-7), N(1,-3)[/tex]
Formula for finding the length of line segment: [tex]\sqrt{(x_{1}-x_{2})^2+(y_{1}-y_{2})^2}[/tex] , where [tex](x_{1}, y_{1})[/tex] and [tex](x_{2}, y_{2})[/tex] are two endpoints.
So, the length of [tex]JK = \sqrt{(-1-(-5))^2+(10-2)^2}= \sqrt{(4)^2+(8)^2}= \sqrt{16+64}= \sqrt{80}[/tex]
and the length of [tex]MN=\sqrt{(9-1)^2+(-7-(-3))^2}= \sqrt{(8)^2+(-4)^2}= \sqrt{64+16}= \sqrt{80}[/tex]
As, the lengths of [tex]JK[/tex] and [tex]MN[/tex] are equal, so we can say that, [tex]JK[/tex] is congruent to [tex]MN[/tex].
