Respuesta :
Answer:
Car A traveled at 55 mph.
Step-by-step explanation:
Suppose, the speed of Car A is [tex]x[/tex] mph.
As Car B traveled 22 mph faster than Car A , so the speed of Car B will be: [tex](x+22) mph[/tex]
Given that, Car A traveled the distance in 2.4 hours and Car B traveled the distance in 4 hours.
As, [tex]Distance= Speed*Time[/tex]
So, the distance traveled by Car A [tex]=2.4x[/tex] miles
and the distance traveled by Car B [tex]=4(x+22)[/tex] miles
Given that, two cars traveled equal distances. So, the equation will be......
[tex]2.4x=4(x+22)\\ \\ 2.4x=4x+88\\ \\ 2.4x-4x=52.8\\ \\ -1.6x=52.8\\ \\ x=\frac{52.8}{-1.6}=-33[/tex]
Thus, the speed of Car A will be -33 mph.
Answer:
The speed of Car A = -55 km/h
Step-by-step explanation:
Given, Time taken by Car A = 2.4 hour
and Time taken by Car B = 4 hour
Also, Car B traveled 22 mph faster than Car A
Let the speed of Car A = x km/h
Then the speed of Car B = (x + 22) km/h
As we know that Distance = Speed × Time
⇒ Distance of Car A = 2.4 × x = 2.4x km
and Distance of Car B = 4 × (x + 22) = 4(x + 22) km
Also it is given that distance traveled by both the car is same.
⇒ 2.4x = 4(x + 22)
⇒ 2.4x = 4x + 88
⇒ 2.4x - 4x = 88
⇒ -1.6x = 88
⇒ x = -55
Thus, the speed of Car A = -55 km/h
and, the speed of Car B = -55 + 22 = -33km/h
