Respuesta :
Hey there!
Given the reaction is :
Cl2(g) + 3 F2(g) = 2 ClF3(g)
The rate of a reaction is given by:
Rate = - Δ[Cl2] / Δt
= (-1/3 Δ[F2] / Δt ) + ( 1/2 Δ[ClF3] / Δt )
Given that : Δ[Cl2] / Δt = - 0.099 M/s
From above rate law:
(- Δ[Cl2] / Δt ) = ( -1/3 Δ[F2] / Δt )
( Δ[F2] / Δt ) = 3 * ( Δ[Cl2] / Δt )
= 3 * ( - 0.099 ) = - 0.297 M/s
Therefore:
Δ[F2]/Δt = -0.297 M/s
Hope That helps!
The rate of consumption of fluorine in the reaction has been -0.297 M/s.
The balanced chemical equation for the reaction has been:
[tex]\rm Cl_2\;+\;3\;F_2\;\rightarrow\;2\;ClF_3[/tex]
According to the reaction for the formation of 1 mole of chlorine fluoride, 1 mole of chlorine reacts with 3 moles of fluorine.
The amount of fluoride consumed in unit time has been 3 times the amount of chlorine consumed in the same time.
The [tex]\rm \dfrac{\Delta Cl_2}{\Delta t}[/tex] has been given to be -0.099 M/s.
It states that amount of chlorine consumed in 1 sec = 0.099 M.
The negative sign has been implied with the deduction in the concentration of Cl per second.
The amount of fluorine consumed at the same time has been 3 times the amount of Cl consumed.
Fluorine consumed ([tex]\rm \Delta\;F_2[/tex]) = 3 [tex]\times[/tex] 0.099 M
Fluorine consumed = 0.297 M.
The amount of fluorine consumed ([tex]\rm \Delta\;F_2[/tex]) per second is 0.297 M.
The rate of the depletion of fluorine in the reaction can be given as:
[tex]\rm \dfrac{\Delta\;F_2}{\Delta t}[/tex]= -0.297 M/s.
The rate of consumption of fluorine in the reaction has been -0.297 M/s.
For more information about the rate of reaction, refer to the link:
https://brainly.com/question/14221385
