Consider the following data showing the initial rate of a reaction (A→products) at several different concentrations of A. [A](M) Initial rate (M/s) 0.15 0.014 0.30 0.113 0.60 0.905. What is the order of the reaction? Express your answer as an integer.

Respuesta :

Given:

A → Products

         [A] M            Rate(M/s)

1.        0.15            0.014

2.       0.30           0.113

3.       0.60           0.905

To determine:

Order of the reaction

Explanation:

The rate of the given reaction can be expressed as:

Rate = k [A]ⁿ-----(1)

where k = rate constant

[A] = concentration of A

n = reaction order

Based on equation (1) the Rates 1 and 2 can be expressed as:

0.014 = k[0.15]ⁿ ------(3)

0.113 = k[0.30]ⁿ-------(4)

Dividing eq (4) by (3) we get:

0.113/0.014 = [0.30/0.15]ⁿ

8 = 2ⁿ

i.e. 2³ = 2ⁿ

n = 3

Ans: Thus, the order of the reaction is 3



The order of the given reaction is [tex]\boxed{3}[/tex] .

Further Explanation:

Order of reaction:

This indicates dependence of rate on power of concentration of reactants involved in the chemical reaction. On the basis of order of reaction, reaction can be first-order, second-order and so on.

Given reaction is as follows :

[tex]A\rightarrow\text{Products}[/tex]

Consider n to be the order of this reaction. So rate of reaction for the given reaction is expressed as follows:

[tex]\text{Rate}=k\left[A\right]^n[/tex]                                                   ...... (1)

Here,

k is the rate constant for the reaction.

[A] is the concentration of A.

n is the order of reaction.

When concentration of A is 0.15 M, rate of reaction is 0.014 M/s.

Substitute 0.15 M for [A] and 0.014 M/s for rate in equation (1).

[tex]\text{0.014\text{M}}=k\left[0.15\right]^n[/tex]                                              ...... (2)

When concentration of A is 0.30 M, rate of reaction is 0.113 M/s.

Substitute 0.30 M for [A] and 0.113 M/s for rate in equation (1).

[tex]\text{0.113\text{M}}=k\left[0.30\right]^n[/tex]                                              ...... (3)

Dividing equation (3) by equation (2),

[tex]\begin{aligned}\dfrac{\text{0.113\text{M}}}{\text{0.014\text{M}}}=&\dfrac{k\left[0.30\right]^n}{k\left[0.15\right]^n}\\\left(2\right)^3=&\left(2\right)^n\end{aligned}[/tex]

Solving for n,

[tex]n=3[/tex]

Therefore order of reaction becomes 3.

Learn more:

1. Rate of chemical reaction: https://brainly.com/question/1569924

2. The main purpose of conducting experiments: https://brainly.com/question/5096428

Answer Details:

Grade: Senior School

Subject: Chemistry

Chapter: Chemical Kinetics

Keywords: order, rate, k, A, products, 3, n, rate constant, order of reaction, 0.15 M, 0.30 M, 0.113 M/s, 0.014 M/s.