Respuesta :

gmany

[tex]|3x+10|=10\iff3x+10=10\ \vee\ 3x+10=-10\qquad|-10\\\\3x=0\ \vee\ 3x=-20\qquad|:3\\\\\boxed{x=0\ \vee\ x=-\dfrac{20}{3}}[/tex]

abidemiokin

Answer:

The possible solutions to the function are x = 0 and x = -20/3

Step-by-step explanation:

Given the equation | 3x + 10 | = 10, the solution to the equation will be two values due to the modulus sign.

Note that any value in a modulus sign can either be positive or negative.

For the positive value of | 3x + 10 | = 10:

3x+10 = 10

3x = 10-10

3x = 0

x = 0

For the negative value of | 3x + 10 | = 10:

-(3x+10) = 10

-3x-10 = 10

-3x = 10+10

-3x = 20

x = -20/3

The possible solutions to the function are x = 0 and x = -20/3

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