The area of a rectangle is the width times the length:
[tex] A = w\cdot l \iff 228 = w\cdot 12 \iff w = \dfrac{228}{12} = 19 [/tex]
The perimeter is twice the sum of the dimensions:
[tex] 2p = 2(12+19) = 2\cdot 31 = 62 [/tex]
The perimeter of the rectangle with dimensions 19 ft*12 ft comes to be 62 square feet.
Suppose the breadth of the rectangle is x.
The perimeter of a rectangle is the sum of all its sides i.e. the sum of two lengths and two breadths.
If length and breadth are a and b respectively then perimeter =2(l+b).
According to the question
Length =12 ft
Area=228 square ft
So, length * breadth = 228
[tex]12x =228[/tex]
[tex]x=\frac{228}{12}[/tex]
x=19
So, breadth of the rectangle =19 ft
So, perimeter = 2(12+19) = 62 square feet.
Hence, the perimeter of the rectangle with dimensions 19 ft*12 ft comes to be 62 square feet.
To get more about rectangles visit:
https://brainly.com/question/25292087
