Answer:
Minimum length of rope needed to span the sides of the prism is 10 units.
Step-by-step explanation:
Let us draw a perpendicular from apex to base BC,Let it be AD since ΔABC is isosceles triangle, that perpendicular will touch mid of base. That is BD=DC=[tex]\frac{6}{2}[/tex]=3
Now we know the angle m∠ABC as 53.13°.
From ΔADC, [tex]cos(53.13)=\frac{DC}{AC} =\frac{3}{(\frac{r}{2} )}[/tex]
[tex]cos(53.13)=\frac{6}{r}[/tex]
[tex]r=\frac{6}{cos(53.13)} = 9.999[/tex]≈10
Hence minimum length of rope needed to span the sides of prism is 10 units.
