Part A
We know that √x = 3
Squaring both sides
x = 3²
⇒ x = 9
Hence, the value of x or the minimum value of x is 9
Part B
([tex]\frac{6}{2\pi }[/tex]*y²) ÷ (0.4*[tex]\frac{y}{x}[/tex]) = ([tex]\frac{6}{2\pi }[/tex]*y²) * [tex]\frac{x}{0.4y}[/tex]
⇒ ([tex]\frac{6}{2\pi }[/tex]*y²) ÷ (0.4*[tex]\frac{y}{x}[/tex]) = [tex]\frac{7.5}{\pi y}[/tex]*yx
