Respuesta :
The reaction is
FeO + Fe3O4 + 1/2 O2---> 2Fe2O3
Thus as shown in the balanced equation two moles of Fe2O3 are formed when 0.5 moles of O2 reacted with mixture of FeO and Fe3O4
moles of Fe2O3 = MAss / Molar mass = 4.141 / 159.69 = 0.0259 moles
So moles of O2 needed = 0.5 X 0.0259 = 0.01295
Mass of O2 = moles X molar mass = 0.01295 X 32 = 0.4144 grams
The mass of oxygen reacted in 3.869 g of a mixture of fe₃O₄ and FeO to form 4.141 g Fe₂O₃ is 0.272 grams.
The balanced chemical equation of the reaction can be represented below:
- Fe₃O₄ + FeO + 1/2 O₂ → 2Fe₂O₃
Heating simply means oxygen was involve in the reactions.
Fe₃O₄ + FeO = 3.869 g
Fe₂O₃ = 4.141 g
let
mass of oxygen reacted = x
Using the law of conservation of mass, the mass of the reactant should be equals to the mass of the product. Therefore,
3.869 + x = 4.141
x = 4.141 - 3.869
x = 0.272 g
mass of Oxygen reacted = 0.272 grams
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