Respuesta :
Let us assume number of quarters coins = x.
We are given that number of dimes is seven more than the number of quarters.
Therefore, number of dimes coins = x+7.
Total value of all coins = $3.50.
We can setup an equation,
0.25 * number of quarter coins + 0.10 * number of dimes coins = 3.50.
0.25x + 0.10(x+7) =3.50
Distributing 0.10(x+7), we get
0.25x +0.10x +0.70 =3.50
Combining like terms, we get
0.35x + 0.70 = 3.50
Subtracting 0.70 from both sides, we get
0.35x + 0.70-0.70 = 3.50-0.70
0.35x = 2.80
Dividing both sides by 0.35
0.35x/0.35 = 2.80/0.35
x = 8.
Therefore, number of quarters = 8.
Number of dimes are 7 more than quarters = 8+7 = 15.
Therefore, 8 quarter and 15 dimes.
Answer:
The number of coins of quarters are 8 and The number of coins of dimes are 15
Step-by-step explanation:
Let the number of coins of quarters be x
We are given that The number of dimes is seven more than the number of quarters
No. of dimes = x+7
1 quarter = $0.25.
x quarters = $0.25 x
1 dime = $0.10
(x+7) dimes = 0.10(x+7)
Now we are given that Ngo has a collection of dimes and quarters with a total value of $3.50.
[tex]0.25 x+0.10(x+7)=3.50[/tex]
[tex]0.25 x+0.10x+0.70=3.50[/tex]
[tex]x=8[/tex]
x+7=8+7=15
Hence the number of coins of quarters are 8 and The number of coins of dimes are 15
