First off,we need to understandthe perimeter of a rectangle:
[tex]2(width + height)[/tex]
We can then proceed to find the width. As it is 6 ft more than it's length,it can be written in:
[tex]w + 6[/tex]
We can then find the equation of the perimeter:
[tex]2((2 + w) + w) = 68 \\ 2(2 + 2w) = 68 \\ 4 + 4w = 68 \\ 4(1 + w) = 68 \\ 1 + w = \frac{68}{4} \\ w = 17 - 1 \\ w = 16[/tex]
When the width is 16ft, the length is:
[tex]16 - 6 \\ = 10[/tex]
The length is 10 ft.
Therefore the dimention of the rectangle is 16ft by 10ft.
Hope it helps!
