Part 1) Kim was hired to paint a house. it took 35 hours to paint and she was paid $840. at this rate, how much would she be paid for a job required 90 hours of work? round answer to nearest hundredth
we know that
by proportion
[tex]\frac{840}{35} \frac{\$}{hours} =\frac{x}{90} \frac{\$}{hours}\\ \\35*x=840*90\\ \\x=(840*90)/35\\ \\x=\$2,160[/tex]
therefore
the answer part 1) is
[tex]\$2,160[/tex]
Part 2) if 4 pounds of meat serves 9 people, how many pounds will be needed to serve 30 people? round answer to nearest hundredth
we know that
by proportion
[tex]\frac{4}{9} \frac{pounds}{people} =\frac{x}{30} \frac{pounds}{people} \\ \\9*x=4*30\\ \\x=(4*30)/9\\ \\x=13.33\ pounds[/tex]
therefore
the answer part 2) is
[tex]13.33\ pounds[/tex]
Part 3) how much interest will you earn if you invest $1225 at a rate of 6% a year for 33 months?
we know that
The simple interest formula is equal to
[tex]I=P(rt)[/tex]
where
I is the Final Interest amount
P is the Principal amount of money to be invested
r is the rate of interest
t is Number of Time Periods in years
in this problem we have
[tex]t=33/12\ years\\ P=\$1,225\\r=0.06[/tex]
substitute in the formula above
[tex]I=\$1,225*(0.06*33/12)=\$202.13[/tex]
therefore
the answer Part 3) is
[tex]\$202.13[/tex]
Part 4) how much money did jonah invest if he received $315 in interest after 51 months? the interest rate was 7% a year. round answer to nearest hundredth
we know that
The simple interest formula is equal to
[tex]I=P(rt)[/tex]
where
I is the Final Interest amount
P is the Principal amount of money to be invested
r is the rate of interest
t is Number of Time Periods in years
in this problem we have
[tex]t=51/12\ years\\ I=\$315\\r=0.07[/tex]
substitute in the formula above
[tex]I=P(rt)[/tex]
solve for P
[tex]P=I/(rt)[/tex]
[tex]P=\$315/(0.07*51/12)=\$1,058.82[/tex]
therefore
the answer Part 4) is
[tex]\$1,058.82[/tex]
