Answer:- 38.2 g.
Solution:- The equation used for solving this type of calorimetry problems is:
[tex]q=mc\Delta T[/tex]
where, q is the heat energy, m is mass, c is specific heat and delta T is the change in temperature.
Water temperature is increasing from 14.5 degree C to 50.0 degree C.
[tex]\Delta T=50.0-14.5[/tex] = 35.5 degree C
q is given as 5680 J and specific heat value is [tex]4.186\frac{J}{g.^0C}[/tex] .
The equation could be rearranged for m as:
[tex]m=\frac{q}{c*\Delta T}[/tex]
Let's plug in the values in it:
[tex]m=\frac{5680}{4.186*35.5}[/tex]
m = 38.2 g
So, the mass of water in the kettle is 38.2 g.
