Answer:- 25.1 g
Solution:- The balanced equation is:
[tex]2NaOH+MgCl_2\rightarrow Mg(OH)_2+2NaCl[/tex]
From given balanced equation, there is 2:1 mol ratio between sodium hydroxide and magnesium hydroxide.
From given molarity and volume, we calculate the moles of NaOH and using mol ratio the moles of magnesium hydroxide are calculated that could easily be converted to grams on multiplying by it's molar mass.
Molar mass of magnesium hydroxide = 24.305 + 2( 15.999 + 1.008)
= 24.305 + 2(17.007)
= 58.319 gram per mol
let's make the set up using dimensional analysis as:
[tex]637mL(\frac{1L}{1000mL})(\frac{1.35molNaOH}{1L})(\frac{1molMg(OH)_2}{2molNaOH})(\frac{58.319gMg(OH)_2}{1molMg(OH)_2})[/tex]
= [tex]25.1gMg(OH)_2[/tex]
So, 25.1 grams of magnesium hydroxide are formed.
