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The sum of three consecutive even integers is 36. Let X represent the first integer X plus to represent the second integer and X +4 represent a third integer which equation can be used to find the first integer

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[tex]x,\ x+2,\ x+4-\text{three consecutive even integers}\\\\\text{The equation:}\\\\x+(x+2)+(x+4)=36\\\\3x+6=36\ \ \ \ |-6\\\\3x=30\ \ \ \ |:3\\\\x=10\\x+2=12\\x+4=14[/tex]

Answer:

X + X + 2 + X + 4 = 30

Step-by-step explanation:

Here, X represent the first integer,

If the other 2 integers are succeeding even integers,

Then second integer = X + 2,

Third integer = X + 4

Thus, the sum of these integers = X + X + 2 + X + 4

According to the question,

Sum of these integers = 36

X + X + 2 + X + 4 = 30

Which is the required equation that is used to find the first integer.

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