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A soccer ball is kicked upward from a hill and then falls to the ground. The height, in feet, of the ball after t sec is modeled by the function h(t) = –16t2 + 26t +12. What is the initial height of the ball? –16 ft –12 ft 12 ft 22 ft

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The height, in feet, of the ball after t sec is modeled by the function [tex]h(t) = -16t^2 + 26t +12.[/tex]

The initial position of the ball is determined at t=0 sec.

Therefore,

[tex]h(0) = -16\cdot 0^2 + 26\cdot 0 +12=12\ ft.[/tex]

Answer: the initial height of the ball is 12 ft (option C).

A function assigns the values. The initial height of the ball is 12 feets. The correct option is C.

What is a Function?

A function assigns the value of each element of one set to the other specific element of another set.

The height, in feet, of the ball after t sec is modeled by the function h(t)=-16t²+26t+12. Now, when the ball will be at its initial height the time will be 0. Therefore, the initial height of the ball is,

h(0) = -16(0)² + 26(0) + 12

h(0) = 0 + 0 + 12

h(0) = 12

Hence, the initial height of the ball is 12 feets. Thus, the correct option is C.

Learn more about Function:

https://brainly.com/question/5245372

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