Here we have to calculate the acceleration of the wagon.
as per the question the mass of the wagon is given as 20 kg
the horizontal force that is applied on the body is 64 newton.
as the perfect unit of the fore is not mentioned it may be 64N or 64 dyne or 64 kgf.
as per Newton's second law of motion we know that the rate of change of momentum is the applied force.from the quantitative definition of Newton's second law we know that applied force is equal to the product of mass and acceleration.
hence [tex]F=mass *acceleration[/tex]
[tex]Acceleration=\frac{force\force}{mass}[/tex]
let F= 64 N,then [tex]a=\frac{64N}{20kg}[/tex]
a=3.2 m/s^2
if F=64kgf=64×9.8 N,then [tex]a=\frac{64*9.8N}{20 kg}[/tex]
=31.36 m/s^2
if F =64 dyne ,the acceleration is found to be 0.0032 cm/s^2 [ans]
