3.4 moles of H₂
The Balance Chemical Equation is as follow,
2 Al + 6 HCl → 3 H₂ + 2 AlCl₃
Calculating moles of H₂ produced,
According to equation,
3.0 moles of HCl produces = 3.0 moles of H₂
So,
3.40 moles of HCl will produce = X moles of H₂
Solving for X,
X = (3.40 mol × 3.0 mol) ÷ 3 mol
X = 3.4 moles of H₂