The correct answer is: " 22. 7 kg " .
__________________________
→ 50.0 lb = " 22. 7 kg " .
__________________________
Explanation:
To solve:
Given: " 50.0 lb. " {that is; " 50 pounds " } ;
→ Convert this value to units of "kg" (kilograms) .
__________________________
Note the exact conversion: " 1 kg = 2.2 lbs. " .
___________________________
So:
→ 50.0 lb. * ([tex]\frac{1 kg}{2.2 lb}[/tex]) = __?__ kg ? ;
→ The units of: " lb." cancel out (to " 1 " ) ;
→ {since: "([tex]\frac{lb.}{lb.}[/tex]) = 1 " } ;
→ to get: "([tex]\frac{50.0}{2.2}[/tex])" kg ;
→ Note that the "2.2" value is an "exact figure" ;
→ So we consider the number of significant figures in the value —
→ " 50.0 " — which has " 3 (three)" significant figures.
→ "([tex]\frac{50}{2.2}[/tex])" kg ;
= " (50 ÷ 2.2) " kg ;
= 22.727272.... kg ;
→ Round to "3 (three)" significant figures :
= " 22. 7 kg .
_______________________
The answer is: " 22. 7 kg " .
__________________________
→ 50.0 lb = " 22. 7 kg " .
__________________________
