a diver dove to a location 6 3/5 meters below sea leavel. He then dove to a second location 8 1/5 meters below sea level. How many meters are there between the two locations?

Respuesta :

First location the diver dove = 6 3/5 meters below sea leavel.

Second location the diver dove = 8 1/5 meters below sea leavel.

Let us convert those mixed fractions into improper fraction.

6 3/5 = [tex]\frac{6*5+3}{5}=\frac{30+2}{5}[/tex] = 33/5.

8 1/5 = [tex]\frac{8*5+1}{5}=\frac{40+1}{5}[/tex] = 41/5.

Now, we need to find the difference in depths of locations diver dove.

41/5 - 33/5 = [tex]\frac{41-33}{5}=\frac{8}{5}[/tex]

So, we got 8/5.

Now, we need to convert 8/5 into mixed fraction.

Dividing 8 by 5, we get quotient=1 and remainder 3.

So, the mixed fraction would be [tex]1 \frac{3}{5}[/tex].

Therefore, we could say [tex]1\frac{3}{5}[/tex] meter is the difference in depths of locations diver dove.

Answer:

There are -1 ⅗ between each location.

Step-by-step explanation: