Solution: We are given:
[tex]\mu=24.8,\sigma =8.5[/tex]
The z-score is given below:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
[tex]=\frac{52-24.8}{8.5}[/tex]
[tex]=\frac{27.2}{8.5} =3.2[/tex]
Therefore, the z-score = 3.2.
The interpretation of z-score is that the team's score is 3.2 standard deviation's above the mean
