Respuesta :
Let's assume
number of matinee admission tickets =x
number of student admission tickets =y
number of regular admission tickets =z
First equation:
regal cinemas sold a total of 8500 movie tickets.
so, we get
[tex]x+y+z=8500[/tex]
Second equation:
a matinee admission costs $5,
student admission is $6 all day,
and regular admissions are $8.50
proceeds totalled 64000
we will get
[tex]5x+6y+8.50z=64000[/tex]
Third equation:
twice as many students tickets were sold as matinee tickets
[tex]-2x+y=0[/tex]
so, we got system of equations as
[tex]x+y+z=8500[/tex]
[tex]5x+6y+8.50z=64000[/tex]
[tex]-2x+y=0[/tex]
we can solve for x , y and z
and we get
[tex]x=971[/tex]
[tex]y=1941[/tex]
[tex]z=5588[/tex]
number of matinee admission tickets =971
number of student admission tickets =1941
number of regular admission tickets =5588...........Answer
Answer:
Number of student ticket is $571
Number of matinee ticket is $1142
Number of regular ticket is $6,787
Step-by-step explanation:
Let number of student ticket be x
Let number of matinee ticket be 2x
Number of regular ticket be 8500 - (x + 2x)
= 8500 - 3x
Total cost is:
$( 5x + ( 6 x 2x) + (8500 - 3x) x 8)
= $( 5x + 12x + 68000 + 24x)
= $( 68000 - 7x)
From the condition given
68000 - 7x = 64000
7x = 4000
x = 4000 / 7
x = 571.43
x = 571
Number of student ticket is $571
Number of matinee ticket is 2 x 571 = $1142
Number of regular ticket = 8500 - (3 x 571)
= 8500 - 1713
= $6,787