Respuesta :
Answer:- 4.93 grams of magnesium sulfate heptahydrate.
Solution:- We have been given with molarity and volume of the solution and asked to calculate the grams of the solute required to make the given solution.
From given volume and molarity we could calculate the moles of the solute and on multiplying with the molar mass of the compound we get the grams of it.
Magnesium sulfate heptahydrate formula is [tex]MgSO_4.7H_2O[/tex] ,
Molar mass of [tex]MgSO_4.7H_2O[/tex] = 24.31 + 32.06 + 4(16) + 14(1.0) + 7(16)
= 24.31 + 32.06 + 64 + 14 + 112
= 246.37 gram per mol
Let's make the set up using dimensional set up as:
[tex]0.100dm^3(\frac{0.200mol}{1dm^3})(\frac{246.37g}{1mol})[/tex]
= 4.93 grams
Hence, 4.93 grams of magnesium sulfate heptahydrate are required to make [tex]0.100dm^3[/tex] of [tex]0.200mol.dm^-^3[/tex] solution.
