Let's assume
number of seats in each row =x
we are given
The number of seats in each row exceeds the number of rows by 20
number of seats = number of rows +20
x = number of rows +20
so, number of rows =x-20
total number of seats = (number of seats in each row)*(number of rows)
so, we can plug values
and we get
[tex]2709=x(x-20)[/tex]
now, we can solve for x
[tex]x^2-20x=2709[/tex]
[tex]x=63,\:x=-43[/tex]
since, number of seats can not be negative
so, number of seats in each row is 63.....................Answer
