Respuesta :
The atomic mass of beryllium (Be) is 9 g/mole
Now, 1 mole of any substance contains avogadro's number of that substance. Therefore:
1 mole of Be contains 6.023 10^23 atoms of Be
In other words:
9 grams of Be contains 6.023*10^23 atoms of Be
Therefore, the mass corresponding to 9.76 * 10^12 atoms of Be is:
= 9 g * 9.76 10^12 atoms/6.023*10^23 atoms
= 1.458 * 10^-10 g (or) 1.46 * 10^-10 g
Answer: The mass of given number of atoms of beryllium is [tex]1.46\times 10^{-10}g[/tex]
Explanation:
Beryllium is the 4th element of the periodic table.
We know that:
Molar mass of beryllium = 9 g/mol
We are given:
Number of beryllium atoms = [tex]9.76\times 10^{12}[/tex]
According to mole concept:
[tex]6.022\times 10^{23}[/tex] number of molecules occupy 1 mole of a gas.
As, [tex]6.022\times 10^{23}[/tex] number of beryllium atoms has a mass of 9 grams.
So, [tex]9.76\times 10^{12}[/tex] atoms of beryllium will have a mass of = [tex]\frac{9g}{6.022\times 10^{23}}\times 9.76\times 10^{12}=1.46\times 10^{-10}g[/tex]
Hence, the mass of given number of atoms of beryllium is [tex]1.46\times 10^{-10}g[/tex]
