A 13.97 g sample of nabr contains 22.34% na by mass. Considering the law of constant composition (definite proportions) how many grams of sodium does a 5.75 g sample of sodium bromide contain?

Respuesta :

As per the law of constant composition, a given sample will always contain the same number of elements that combine in the same mass proportion.

Therefore if a sample of 13.97 g of NaBr contains 22.39 % of Na by mass then,  a sample of 5.75 g of NaBr would also contain 22.39% Na by mass

Hence:

Mass of Na = 5.75 g * 22.39/100 = 1.287 g

5.75 g of NaBr would contain 1.29 g of Na

1.287 grams of sodium, a 5.75 g sample of sodium bromide will contain.

What is the law of constant composition?

The law of definite proportions is often known as Proust's law or the law of constant composition.

It holds that a chemical compound's component elements are always present in a fixed ratio (by mass) regardless of its source or method of creation.

By the law:

A sample of 13.97 g of NaBr contains 22.39 % of Na, then a sample of 5.75 g of NaBr would also contain 22.39% Na.

Hence,

[tex]\bold{Mass\; of\; Na = 5.75 g \times \dfrac{22.39}{100} = 1.287 g}[/tex]

Thus, 5.75 g sample of sodium bromide contains 1.287 g Na.

Learn more about Proust's law, here:

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