Respuesta :
Assuming that the dimensions are proportional, we have the following relationship:
[tex] \frac{x}{5+\frac{1}{3}} = \frac{54}{2} [/tex]
Where,
x: approximate height of the statue
Clearing the value of x we have:
[tex] x=\frac{54}{2}(5+\frac{1}{3}) [/tex]
[tex] x = 144 [/tex]
On the other hand, we know that:
[tex] 1feet = 12inches [/tex]
Then, in relative terms, the relationship between the heights of the statue is:
[tex] \frac{144-(143+\frac{9}{12}}{143+\frac{9}{12}}(100) [/tex]
[tex] 1.7 [/tex]%
Answer:
The approximate height of the statue is:
[tex] x = 144 [/tex]
The difference with respect to the actual height is 1.7%.
Answer:
The approximate height is 0.251 inches close to the statue's actual height of 143 feet, 9 inches from heel to top of head .
Step-by-step explanation:
Given :
The length of the statue's right arm is 54 feet.
The student's right arm is 2 feet long and her height is 5 and one third feet.
To Find : How close is the approximate height to the statue's actual height of 143 feet, 9 inches from heel to top of head?
Solution:
Let the height of the statue be x
The length of the statue's right arm is 54 feet.
The student's right arm is 2 feet long
Ratio of their arms length = 54:2
Height of girl = [tex]5\frac{1}{3} =\frac{16}{3}[/tex]
Ratio of their heights = [tex]x: \frac{16}{3}[/tex]
So, [tex]\frac{x}{\frac{16}{3}}=\frac{54}{2}[/tex]
[tex]x=\frac{16}{3} \times \frac{54}{2}[/tex]
[tex]x=8 \times 18 [/tex]
[tex]x=144 [/tex]
So, the approximate height is 144 feet.
Actual height of statue is 143 feet, 9 inches = [tex]143 + 9 \times 0.0833333=143.749[/tex]
So, the difference between approximate height and actual height:
= 144-143.749
=0.251
Hence the approximate height is 0.251 inches close to the statue's actual height of 143 feet, 9 inches from heel to top of head .
